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QJEEM22Phc6fe: JEE Main 2022 Physics - Class 12 JEEM22Phc6fe Solution: The equation of current in a purely inductive circuit is . If…

The equation of current in a purely inductive circuit is 5sin⁡(49 πt−30∘)5 \sin \left(49\, \pi t-30^{\circ}\right) . If the inductance is 30 mH30 \,\mathrm{mH} then the equation for the voltage across the inductor, will be :

{\left\{\right. Let π=227}\left.\pi=\frac{22}{7}\right\}

Multiple Choice Options

  • A 1.47sin⁡(49πt−30∘)1.47 \sin \left(49 \pi t-30^{\circ}\right)
  • B 1.47sin⁡(49πt+60∘)1.47 \sin \left(49 \pi t+60^{\circ}\right)
  • C 23.1sin⁡(49πt−30∘)23.1 \sin \left(49 \pi t-30^{\circ}\right)
  • D 23.1sin⁡(49πt+60∘)23.1 \sin \left(49 \pi t+60^{\circ}\right)

Step-by-Step Verified Solution

JEE Main 2022 (Online) 28th July Morning Shift Physics - Alternating Current Question 61 English Explanation

V(t)=IωLsin⁡(49πt−30∘+90∘)V(t) = I\omega L\sin (49\pi t - 30^\circ + 90^\circ )

=5×49π×301000sin⁡(49πt+60∘)= 5 \times 49\pi \times {{30} \over {1000}}\sin (49\pi t + 60^\circ )

=23.1sin⁡(49πt+60∘)= 23.1\sin (49\pi t + 60^\circ )

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