Verified Solution • 2025–26 Session moderate

QJEEM22Phc43f: JEE Main 2022 Physics - Class 12 JEEM22Phc43f Solution: Two parallel, long wires are kept 0.20 m apart in vacuum, each…

Two parallel, long wires are kept 0.20 m apart in vacuum, each carrying current of x A in the same direction. If the force of attraction per meter of each wire is 2 ×\times 10 −- 6 N, then the value of x is approximately :

Multiple Choice Options

  • A 1
  • B 2.4
  • C 1.4
  • D 2

Step-by-Step Verified Solution

dFdl=2×10−6{{dF} \over {dl}} = 2 \times {10^{ - 6}} N/m =μ0i1i22πd= {{{\mu _0}{i_1}{i_2}} \over {2\pi d}}

2×10−6=2×10−7×x20.22 \times {10^{ - 6}} = {{2 \times {{10}^{ - 7}} \times {x^2}} \over {0.2}}

x=2≃1.4x = \sqrt 2 \simeq 1.4

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