QJEEM22Phbc19: JEE Main 2022 Physics - Class 11 JEEM22Phbc19 Solution: If momentum [P], area [ A ] and time [ T ] are taken as…

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If momentum [P], area $[A]$ and time $[T]$ are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is :

Accepted Answer

$[η] = [M L^{- 1} T^{- 1}]$

Now if $[η] = [P]^{a} [A]^{b} [T]^{c}$

$\Rightarrow [M L^{- 1} T^{- 1}] = [M L^{1} T^{- 1}]^{a} [L^{2}]^{b} [T]^{c}$

$\Rightarrow a = 1, a + 2 b = - 1, - a + c = - 1$

$\Rightarrow a = 1, b = - 1, c = 0$

$\Rightarrow [η] = [P] [A]^{- 1} [T]^{0}$

$= [P A^{- 1} T^{0}]$

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