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QJEEM22Phbb97: JEE Main 2022 Physics - Class 12 JEEM22Phbb97 Solution: An inductor of 0.5 mH, a capacitor of 200 F and a resistor of 2 …

An inductor of 0.5 mH, a capacitor of 200 μ\mu F and a resistor of 2 Ω\Omega are connected in series with a 220 V ac source. If the current is in phase with the emf, the frequency of ac source will be ____________ ×\times 102 Hz.

Step-by-Step Verified Solution

Current will be in phase with emf when

ωL=1ωC\omega L = {1 \over {\omega C}}

⇒ω=1LC=15×10−4×2×10−4\Rightarrow \omega = {1 \over {\sqrt {LC} }} = {1 \over {\sqrt {5 \times {{10}^{ - 4}} \times 2 \times {{10}^{ - 4}}} }}

⇒ω=10410\Rightarrow \omega = {{{{10}^4}} \over {\sqrt {10} }} rad/s

⇒f=12π×10410\Rightarrow f = {1 \over {2\pi }} \times {{{{10}^4}} \over {\sqrt {10} }} Hz

⇒\Rightarrow f ≃\simeq 500 Hz

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