Verified Solution • 2025–26 Session moderate

QJEEM22Phb85e: JEE Main 2022 Physics - Class 11 JEEM22Phb85e Solution: One end of a massless spring of spring constant k and natural…

One end of a massless spring of spring constant k and natural length l0 is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity ω about an axis passing through fixed end, then the elongation of the spring will be :

Multiple Choice Options

  • A k−mω2l0mω2
  • B mω2l0k+mω2
  • C mω2l0k−mω2
  • D k+mω2l0mω2

Step-by-Step Verified Solution

mω2(l0+x)=kx

⇒mω2l0=(k−mω2)×x

⇒x=mω2l0(k−mω2)

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