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QJEEM22Phb735: JEE Main 2022 Physics - Class 12 JEEM22Phb735 Solution: A hydrogen atom in its first excited state absorbs a photon of…

A hydrogen atom in its first excited state absorbs a photon of energy x × 10−2 eV and excited to a higher energy state where the potential energy of electron is −1.08 eV. The value of x is ______________.

Step-by-Step Verified Solution

As, En=P⋅En2=−1.082=−0.544E_{n}=\frac{P \cdot E_{n}}{2}=-\frac{1.08}{2}=-0.544

 So, ΔE,Ef−Ei=−0.544−(−13.622)=3.4−0.544≈2.86eV=286×10−2eV

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