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QJEEM22Phb65f: JEE Main 2022 Physics - Class 11 JEEM22Phb65f Solution: Assume there are two identical simple pendulum clocks. Clock -…

Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located at a height h above the earth surface. Clock - 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of h is -

(consider radius of earth RE=6400 kmR_{E}=6400 \mathrm{~km} and g\mathrm{g} on earth 10 m/s210 \mathrm{~m} / \mathrm{s}^{2} )

Multiple Choice Options

  • A 1200 km
  • B 1600 km
  • C 3200 km
  • D 4800 km

Step-by-Step Verified Solution

T∝1/gT \propto \sqrt {1/g}

⇒T1T2=g2g1=RR+h\Rightarrow {{{T_1}} \over {{T_2}}} = \sqrt {{{{g_2}} \over {{g_1}}}} = {R \over {R + h}}

46=RR+h{4 \over 6} = {R \over {R + h}}

⇒h=R/2\Rightarrow h = R/2

=3200= 3200 km

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