Verified Solution • 2025–26 Session moderate

QJEEM22Phb335: JEE Main 2022 Physics - Class 12 JEEM22Phb335 Solution: In a Young's double slit experiment, a laser light of 560 nm…

In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is __________ nm.

Step-by-Step Verified Solution

λ=560×10−9\lambda = 560 \times {10^{ - 9}}

B1=7.2×10−3{B_1} = 7.2 \times {10^{ - 3}}

B2=8.1×10−3{B_2} = 8.1 \times {10^{ - 3}}

B1B2=λ1λ2{{{B_1}} \over {{B_2}}} = {{{\lambda _1}} \over {{\lambda _2}}}

⇒λ2=560×10−9×8.1×10−37.2×10−3\Rightarrow {\lambda _2} = {{560 \times {{10}^{ - 9}} \times 8.1 \times {{10}^{ - 3}}} \over {7.2 \times {{10}^{ - 3}}}}

=6.3×10−7= 6.3 \times {10^{ - 7}} m

=630= 630 nm

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