QJEEM22Phab6b: JEE Main 2022 Physics - Class 12 JEEM22Phab6b Solution: Magnetic flux (in weber) in a closed circuit of resistance 20 Ω …

Question

Verified Solution • 2025–26 Session moderate

QJEEM22Phab6b: JEE Main 2022 Physics - Class 12 JEEM22Phab6b Solution: Magnetic flux (in weber) in a closed circuit of resistance 20 Ω …

Magnetic flux (in weber) in a closed circuit of resistance 20 $Ω$ varies with time t(s) at $ϕ$ = 8t² $-$ 9t + 5. The magnitude of the induced current at t = 0.25 s will be ____________ mA.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

$R = 20 Ω$

$ϕ = 8 t^{2} - 9 t + 5$

$ε = | - \frac{d ϕ}{d t} | = | 16 t - 9 | = | 16 (0.25) - 9 | = 5$

$i = \frac{ε}{R} = \frac{5}{20} = 0.25 A = \frac{0.25}{10^{3}} \times 10^{3} A = 250 m A$

QJEEM22Phab6b: JEE Main 2022 Physics - Class 12 JEEM22Phab6b Solution: Magnetic flux (in weber) in a closed circuit of resistance 20 Ω …

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation