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QJEEM22Phaad3: JEE Main 2022 Physics - Class 11 JEEM22Phaad3 Solution: A ball is projected with kinetic energy E, at an angle of to…

A ball is projected with kinetic energy E, at an angle of 60∘60^{\circ} to the horizontal. The kinetic energy of this ball at the highest point of its flight will become :

Multiple Choice Options

  • A Zero
  • B E2\frac{E}{2}
  • C E4\frac{E}{4}
  • D E

Step-by-Step Verified Solution

K.E.=E=12mv2K.E. = E = {1 \over 2}m{v^2}

at highest point

K.E′=12mv2cos⁡2θK.E' = {1 \over 2}m{v^2}{\cos ^2}\theta

=12mv2(14)= {1 \over 2}m{v^2}\left( {{1 \over 4}} \right)

=E4= {E \over 4}

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