Verified Solution • 2025–26 Session moderate

QJEEM22Phaa5d: JEE Main 2022 Physics - Class 12 JEEM22Phaa5d Solution: Three identical charged balls each of charge 2 C are suspended…

Three identical charged balls each of charge 2 C are suspended from a common point P by silk threads of 2 m each (as shown in figure). They form an equilateral triangle of side 1m.

The ratio of net force on a charged ball to the force between any two charged balls will be :

JEE Main 2022 (Online) 27th June Evening Shift Physics - Electrostatics Question 106 English

Multiple Choice Options

  • A 1:01
  • B 1:04
  • C 3\sqrt3 : 2
  • D 3\sqrt3 : 1

Step-by-Step Verified Solution

JEE Main 2022 (Online) 27th June Evening Shift Physics - Electrostatics Question 106 English Explanation

Fnet on charge 3, F1=3kq212{F_1} = {{\sqrt 3 k{q^2}} \over {{1^2}}}

Force between any 2 charges

F2=kq212{F_2} = {{k{q^2}} \over {{1^2}}}

So, F1F2=3{{{F_1}} \over {{F_2}}} = \sqrt 3

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring