Verified Solution • 2025–26 Session moderate

QJEEM22Pha65b: JEE Main 2022 Physics - Class 12 JEEM22Pha65b Solution: A hydrogen atom in its ground state absorbs 10.2 eV of energy.…

A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of :

(Given, Planck's constant = 6.6 ×\times 10 −- 34 Js).

Multiple Choice Options

  • A 2.10 ×\times 10 −- 34 Js
  • B 1.05 ×\times 10 −- 34 Js
  • C 3.15 ×\times 10 −- 34 Js
  • D 4.2 ×\times 10 −- 34 Js

Step-by-Step Verified Solution

−13.6+10.2=−13.6n2- 13.6 + 10.2 = {{ - 13.6} \over {{n^2}}}

⇒13.6n2=3.4\Rightarrow {{13.6} \over {{n^2}}} = 3.4

⇒n=2\Rightarrow n = 2

⇒ΔL=2×h2λ−1×h2λ\Rightarrow \Delta L = 2 \times {h \over {2\lambda }} - 1 \times {h \over {2\lambda }}

=h2λ= {h \over {2\lambda }}

⇒ΔL≃1.05×10−34\Rightarrow \Delta L \simeq 1.05 \times {10^{ - 34}} Js

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