Verified Solution • 2025–26 Session moderate

QJEEM22Pha405: JEE Main 2022 Physics - Class 12 JEEM22Pha405 Solution: The height of a transmitting antenna at the top of a tower is…

The height of a transmitting antenna at the top of a tower is 25 m and that of receiving antenna is, 49 m. The maximum distance between them, for satisfactory communication in LOS (Line-Of-Sight) is K 5\sqrt5 ×\times 102 m. The value of K is ___________.

(Assume radius of Earth is 64 ×\times 10+5 m) [Calculate upto nearest integer value]

Step-by-Step Verified Solution

d=2htRe+2×hRRed = \sqrt {2{h_t}{R_e}} + \sqrt {2 \times {h_R}{R_e}}

=2×25×64×105+2×49×64×105= \sqrt {2 \times 25 \times 64 \times {{10}^5}} + \sqrt {2 \times 49 \times 64 \times {{10}^5}}

=80005+112005= 8000\sqrt 5 + 11200\sqrt 5 m

=192005= 19200\sqrt 5 m

=1925+102= 192\sqrt 5 + {10^2} m

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring