QJEEM22Pha1dd: JEE Main 2022 Physics - Class 12 JEEM22Pha1dd Solution: Current measured by the ammeter (A) in the reported circuit…

For ${I_{10}} = 0$

${R \over 3} = {4 \over 6}$

$\Rightarrow R = 2\,\Omega$

$\Rightarrow {I_A} = {{36 \times (6 + 9)} \over {6 \times 9}}$

$= {{36 \times 15} \over {6 \times 9}} = 10$ A