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QJEEM22Ph99fa: JEE Main 2022 Physics - Class 11 JEEM22Ph99fa Solution: In an experiment to find out the diameter of wire using screw…

In an experiment to find out the diameter of wire using screw gauge, the following observations were noted :

JEE Main 2022 (Online) 29th July Morning Shift Physics - Units & Measurements Question 70 English

(A) Screw moves 0.5 mm0.5 \mathrm{~mm} on main scale in one complete rotation

(B) Total divisions on circular scale =50=50

(C) Main scale reading is 2.5 mm2.5 \mathrm{~mm}

(D) 45th 45^{\text {th }} division of circular scale is in the pitch line

(E) Instrument has 0.03 mm negative error

Then the diameter of wire is :

Multiple Choice Options

  • A 2.92 mm
  • B 2.54 mm
  • C 2.98 mm
  • D 3.45 mm

Step-by-Step Verified Solution

L.C. = 0.550{{0.5} \over {50}} mm = 0.01 mm

d=(2.5+45×0.01+0.03)d = (2.5 + 45 \times 0.01 + 0.03) mm

= 2.98

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