QJEEM22Ph9509: JEE Main 2022 Physics - Class 12 JEEM22Ph9509 Solution: A uniform electric field E = ( 8   m / e ) V / m is…

A uniform electric field $$\mathrm{E}=(8\mathrm{m}/\mathrm{e})\mathrm{V}/\mathrm{m}$$ is created between two parallel plates of length $$1\mathrm{m}$$ as shown in figure, (where $$\mathrm{m}=$$ mass of electron and e = charge of electron). An electron enters the field symmetrically between the plates with a speed of $$2\mathrm{m}/\mathrm{s}$$. The angle of the deviation $$(\theta )$$ of the path of the electron as it comes out of the field will be _________.