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QJEEM22Ph93cd: JEE Main 2022 Physics - Class 11 JEEM22Ph93cd Solution: Consider a cylindrical tank of radius is filled with water. The …

Consider a cylindrical tank of radius 1 m1 \mathrm{~m} is filled with water. The top surface of water is at 15 m15 \mathrm{~m} from the bottom of the cylinder. There is a hole on the wall of cylinder at a height of 5 m5 \mathrm{~m} from the bottom. A force of 5×105 N5 \times 10^{5} \mathrm{~N} is applied an the top surface of water using a piston. The speed of ifflux from the hole will be : (given atmospheric pressure PA=1.01×105 Pa\mathrm{P}_{\mathrm{A}}=1.01 \times 10^{5} \mathrm{~Pa} , density of water ρW=1000 kg/m3\rho_{\mathrm{W}}=1000 \mathrm{~kg} / \mathrm{m}^{3} and gravitational acceleration g=10 m/s2\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2} )

JEE Main 2022 (Online) 28th July Evening Shift Physics - Properties of Matter Question 116 English

Multiple Choice Options

  • A 11.6 m/s
  • B 10.8 m/s
  • C 17.8 m/s
  • D 14.4 m/s

Step-by-Step Verified Solution

By Bernoulli's theorem,

5×105π(1)2+ρg(10)=1.01×105+12ρ(v)2{{5 \times {{10}^5}} \over {\pi {{(1)}^2}}} + \rho g(10) = 1.01 \times {10^5} + {1 \over 2}\rho {(v)^2}

⇒v2=200+1061000π−202\Rightarrow {v^2} = 200 + {{{{10}^6}} \over {1000\pi }} - 202

⇒v≃17.8\Rightarrow v \simeq 17.8 m/s

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