QJEEM22Ph90e3: JEE Main 2022 Physics - Class 12 JEEM22Ph90e3 Solution: A deuteron and a proton moving with equal kinetic energy enter…

Question

Verified Solution • 2025–26 Session moderate

QJEEM22Ph90e3: JEE Main 2022 Physics - Class 12 JEEM22Ph90e3 Solution: A deuteron and a proton moving with equal kinetic energy enter…

A deuteron and a proton moving with equal kinetic energy enter into a uniform magnetic field at right angle to the field. If r_d and r_p are the radii of their circular paths respectively, then the ratio $\frac{r_{d}}{r_{p}}$ will be $\sqrt{x}$ : 1 where x is __________.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

$R = \frac{\sqrt{2 m K}}{q B}$

So, $\frac{r_{d}}{r_{p}} = \frac{\sqrt{m_{d}} / q_{d}}{\sqrt{m_{p}} / q_{p}}$

$= \sqrt{2}$

So $x = 2$

QJEEM22Ph90e3: JEE Main 2022 Physics - Class 12 JEEM22Ph90e3 Solution: A deuteron and a proton moving with equal kinetic energy enter…

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation