QJEEM22Ph8f59: JEE Main 2022 Physics - Class 11 JEEM22Ph8f59 Solution: In the wave equation the velocity of the wave will be:

Question

Verified Solution • 2025–26 Session moderate

In the wave equation

$y=0.5 \sin \frac{2 \pi}{\lambda}(400 \mathrm{t}-x) \,\mathrm{m}$

the velocity of the wave will be:

Accepted Answer

${v_{wave}} = \left| {{{coefficient\,of\,t} \over {coefficient\,of\,x}}} \right|$

$= {{400} \over 1} = 400$ m/s

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