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QJEEM22Ph8f4f: JEE Main 2022 Physics - Class 11 JEEM22Ph8f4f Solution: A transverse wave is represented by y = 2 sin ⁡ ( ω t − k x )…

A transverse wave is represented by y=2sin⁡(ωt−kx)cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be :

Multiple Choice Options

  • A 4π
  • B 2π
  • C π
  • D 2

Step-by-Step Verified Solution

ωk=Aω

⇒k=1A=12cm

⇒2πλ=12cm

⇒λ=4πcm

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