Verified Solution • 2025–26 Session moderate

QJEEM22Ph8eff: JEE Main 2022 Physics - Class 11 JEEM22Ph8eff Solution: Given below are two statements : Statement I : The average…

Given below are two statements :

Statement I : The average momentum of a molecule in a sample of an ideal gas depends on temperature.

Statement II : The rms speed of oxygen molecules in a gas is vv . If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v2 v .

In the light of the above statements, choose the correct answer from the options given below :

Multiple Choice Options

  • A Both Statement I and Statement II are true
  • B Both Statement I and Statement II are false
  • C Statement I is true but Statement II is false
  • D Statement I is false but Statement II is true

Step-by-Step Verified Solution

Average momentum =⟨P→⟩=0= \left\langle {\overrightarrow P } \right\rangle = 0

vrms=3RTM{v_{rms}} = \sqrt {{{3RT} \over M}}

If temperature is doubled and oxygen atoms are used then

vrms′=3R(2T)M/2=4 vrmsv{'_{rms}} = \sqrt {{{3R(2T)} \over {M/2}}} = 4\,{v_{rms}}

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