QJEEM22Ph8e2b: JEE Main 2022 Physics - Class 11 JEEM22Ph8e2b Solution: The dimensions of ( B 2 μ 0 ) will be : (if μ 0 : permeability…

Question

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The dimensions of $(\frac{B^{2}}{μ_{0}})$ will be :

(if $μ_{0}$ : permeability of free space and $B$ : magnetic field)

Accepted Answer

$[\frac{B^{2}}{μ_{0}}] =$ [Energy density]

$= \frac{M L^{2} T^{- 2}}{L^{3}} = M L^{- 1} T^{- 2}$

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