QJEEM22Ph8c46: JEE Main 2022 Physics - Class 11 JEEM22Ph8c46 Solution: A block of mass 2 kg moving on a horizontal surface with speed…

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QJEEM22Ph8c46: JEE Main 2022 Physics - Class 11 JEEM22Ph8c46 Solution: A block of mass 2 kg moving on a horizontal surface with speed…

A block of mass 2 kg moving on a horizontal surface with speed of 4 ms^{$-$ 1} enters a rough surface ranging from x = 0.5 m to x = 1.5 m. The retarding force in this range of rough surface is related to distance by F = $-$ kx where k = 12 Nm^{$-$ 1}. The speed of the block as it just crosses the rough surface will be :

Multiple Choice Options

A zero
B 1.5 ms−1
C 2.0 ms−1
D 2.5 ms−1

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Accepted Answer

$F = - 12 x$

$m v \frac{d v}{d x} = - 12 x$

$\int_{4}^{v} v d v = - 6 \int_{0.5}^{1.5} x d x$ ( $m = 2$ kg)

$\frac{v^{2} - 16}{2} = - 6 [\frac{{1.5}^{2} - {0.5}^{2}}{2}]$

$\frac{v^{2} - 16}{2} = - 6$

$v = 2$ m/sec

QJEEM22Ph8c46: JEE Main 2022 Physics - Class 11 JEEM22Ph8c46 Solution: A block of mass 2 kg moving on a horizontal surface with speed…

Multiple Choice Options

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