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QJEEM22Ph8966: JEE Main 2022 Physics - Class 12 JEEM22Ph8966 Solution: A long wire is broken into two unequal parts and . The part of…

A 1 m1 \mathrm{~m} long wire is broken into two unequal parts X\mathrm{X} and Y\mathrm{Y} . The X\mathrm{X} part of the wire is streched into another wire W. Length of WW is twice the length of XX and the resistance of W\mathrm{W} is twice that of Y\mathrm{Y} . Find the ratio of length of X\mathrm{X} and Y\mathrm{Y} .

Multiple Choice Options

  • A 1:04
  • B 1:02
  • C 4:01
  • D 2:01

Step-by-Step Verified Solution

JEE Main 2022 (Online) 29th July Evening Shift Physics - Current Electricity Question 109 English Explanation RXRY=ℓXℓY\frac{\mathrm{R}_{\mathrm{X}}}{\mathrm{R}_{\mathrm{Y}}}=\frac{\ell_{\mathrm{X}}}{\ell_{\mathrm{Y}}}

When wire is stretched to double of its length, then resistance becomes 4 times

amp;RW=4RX=2RYamp;RXRY=12\begin{aligned}&\mathrm{R}_{\mathrm{W}}=4 \mathrm{R}_{\mathrm{X}}=2 \mathrm{R}_{\mathrm{Y}} \\\\&\frac{\mathrm{R}_{\mathrm{X}}}{\mathrm{R}_{\mathrm{Y}}}=\frac{1}{2}\end{aligned}

So. ℓxℓy=12\frac{\ell_{\mathrm{x}}}{\ell_{\mathrm{y}}}=\frac{1}{2}

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