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QJEEM22Ph891c: JEE Main 2022 Physics - Class 11 JEEM22Ph891c Solution: A student in the laboratory measures thickness of a wire using…

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.19 mm and 1.20 mm. The percentage error is x121%{x \over {121}}\% . The value of x is ____________.

Step-by-Step Verified Solution

Imean=1.22+1.23+1.19+1.204=1.21{I_{mean}} = {{1.22 + 1.23 + 1.19 + 1.20} \over 4} = 1.21

ΔImean=0.01+0.02+0.02+0.014=0.015\Delta {I_{mean}} = {{0.01 + 0.02 + 0.02 + 0.01} \over 4} = 0.015

So % I=ΔImeanImean×100=0.0151.21×100=150121%I = {{\Delta {I_{mean}}} \over {{I_{mean}}}} \times 100 = {{0.015} \over {1.21}} \times 100 = {{150} \over {121}}\%

x=150x = 150

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