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QJEEM22Ph88b1: JEE Main 2022 Physics - Class 11 JEEM22Ph88b1 Solution: For a perfect gas, two pressures P 1 and P 2 are shown in…

For a perfect gas, two pressures P1 and P2 are shown in figure. The graph shows :

JEE Main 2022 (Online) 27th June Evening Shift Physics - Heat and Thermodynamics Question 172 English

Multiple Choice Options

  • A P1 > P2
  • B P1 < P2
  • C P1 = P2
  • D Insufficient data to draw any conclusion

Step-by-Step Verified Solution

As per ideal gas equation, V=nRPTV = {{nR} \over P}T

⇒\Rightarrow Slope of V-T graph is inversely proportional to P.

As m2 > m1 ⇒\Rightarrow P1 > P2

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