Verified Solution • 2025–26 Session moderate

QJEEM22Ph85e8: JEE Main 2022 Physics - Class 12 JEEM22Ph85e8 Solution: In Young's double slit experiment performed using a…

In Young's double slit experiment performed using a monochromatic light of wavelength λ, when a glass plate (μ = 1.5) of thickness xλ is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of x will be :

Multiple Choice Options

  • A 3
  • B 2
  • C 1.5
  • D 0.5

Step-by-Step Verified Solution

For the intensity to remain same the position must be of a maxima so path difference must be nλ so

(1.5 − 1) xλ = nλ

x = 2n (n = 0, 1, 2 ....)

So, value of x will be

x = 0, 2, 4, 6 ....

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