Verified Solution • 2025–26 Session moderate

QJEEM22Ph7f55: JEE Main 2022 Physics - Class 12 JEEM22Ph7f55 Solution: A proton and an alpha particle of the same velocity enter in a…

A proton and an alpha particle of the same velocity enter in a uniform magnetic field which is acting perpendicular to their direction of motion. The ratio of the radii of the circular paths described by the alpha particle and proton is :

Multiple Choice Options

  • A 1:04
  • B 4:01
  • C 2:01
  • D 1:02

Step-by-Step Verified Solution

R=mvqBR=\frac{m v}{q B}

RαRP=MαMP×qPqα\frac{\mathrm{R}_\alpha}{\mathrm{R}_{\mathrm{P}}}=\frac{\mathrm{M}_\alpha}{\mathrm{M}_{\mathrm{P}}} \times \frac{\mathrm{q}_{\mathrm{P}}}{\mathrm{q}_\alpha}

RαRP=41×12=2\frac{\mathrm{R}_\alpha}{\mathrm{R}_{\mathrm{P}}}=\frac{4}{1} \times \frac{1}{2}=2

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