Verified Solution • 2025–26 Session moderate

QJEEM22Ph7b51: JEE Main 2022 Physics - Class 12 JEEM22Ph7b51 Solution: A closely wounded circular coil of radius 5 cm produces a…

A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68×10−4 T37.68 \times 10^{-4} \mathrm{~T} at its center. The current through the coil is _________A.

[Given, number of turns in the coil is 100 and π=3.14\pi=3.14 ]

Step-by-Step Verified Solution

B=μ0nI2RB = {{{\mu _0}nI} \over {2R}}

37.68×10−4=4π×10−7100 I2×5×10−237.68 \times {10^{ - 4}} = {{4\pi \times {{10}^{ - 7}}100\,I} \over {2 \times 5 \times {{10}^{ - 2}}}}

I=300 A100I = {{300\,A} \over {100}}

=3 A= 3\,A

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