Verified Solution • 2025–26 Session moderate

QJEEM22Ph7a33: JEE Main 2022 Physics - Class 12 JEEM22Ph7a33 Solution: The aperture of the objective is 24.4 cm. The resolving power…

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 Ao\mathop A\limits^o is used to see th object will be :

Multiple Choice Options

  • A 8.1 ×\times 106
  • B 10.0 ×\times 107
  • C 8.2 ×\times 105
  • D 1.0 ×\times 10 −- 8

Step-by-Step Verified Solution

R.P.=11.22 λ/aR.P. = {1 \over {1.22\,\lambda /a}}

=24.4×10−21.22×2440×10−10= {{24.4 \times {{10}^{ - 2}}} \over {1.22 \times 2440 \times {{10}^{ - 10}}}}

=8.2×105= 8.2 \times {10^5}

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