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QJEEM22Ph7664: JEE Main 2022 Physics - Class 12 JEEM22Ph7664 Solution: A singly ionized magnesium atom (A = 24) ion is accelerated to…

A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 keV, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be _____________ cm.

Step-by-Step Verified Solution

R=mvqBR = {{mv} \over {qB}}

R=2mKEqBR = {{\sqrt {2mKE} } \over {qB}}

=2×24×1.67×10−27×5×1.6×10−161.6×10−19×0.5= {{\sqrt {2 \times 24 \times 1.67 \times {{10}^{ - 27}} \times 5 \times 1.6 \times {{10}^{ - 16}}} } \over {1.6 \times {{10}^{ - 19}} \times 0.5}}

= 10.009 cm = 10 cm

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