Verified Solution • 2025–26 Session moderate

QJEEM22Ph75cf: JEE Main 2022 Physics - Class 12 JEEM22Ph75cf Solution: A charge of 4 μ C is to be divided into two. The distance…

A charge of $4 μ C$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be :

Multiple Choice Options

A 1μC and 3μC
B 2μC and 2μC
C 0 and 4μC
D 1.5μC and 2.5μC

Step-by-Step Verified Solution

JEE Main 2022 (Online) 27th July Evening Shift Physics - Electrostatics Question 91 English Explanation

so $F = \frac{k q (4 - q) \times 10^{- 12}}{r^{2}}$

so F_max will be at q = 2 $μ$ C

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring