Verified Solution • 2025–26 Session moderate

QJEEM22Ph7539: JEE Main 2022 Physics - Class 12 JEEM22Ph7539 Solution: The energy band gap of semiconducting material to produce…

The energy band gap of semiconducting material to produce violet (wavelength = 4000 Ao\mathop A\limits^o ) LED is ______________ eV\mathrm{eV} . (Round off to the nearest integer).

Step-by-Step Verified Solution

Energy corresponding to wavelength 4000 Ao\mathop A\limits^o

E=hcπE = {{hc} \over \pi }

=6.6×10−34×3×1084000×10−10×1.6×10−19= {{6.6 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {4000 \times {{10}^{ - 10}} \times 1.6 \times {{10}^{ - 19}}}} eV

=124004000= {{12400} \over {4000}}

=3.1=3.1 eV

≈\approx 3 eV

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring