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QJEEM22Ph6f72: JEE Main 2022 Physics - Class 11 JEEM22Ph6f72 Solution: The diameter of an air bubble which was initially , rises…

The diameter of an air bubble which was initially 2 mm2 \mathrm{~mm} , rises steadily through a solution of density 1750 kg m−31750 \mathrm{~kg} \mathrm{~m}^{-3} at the rate of 0.35 cms−10.35 \,\mathrm{cms}^{-1} . The coefficient of viscosity of the solution is _________ poise (in nearest integer). (the density of air is negligible).

Step-by-Step Verified Solution

F=6πηrvF = 6\pi \eta rv

43πr3ρlg=6πηrv{4 \over 3}\pi {r^3}{\rho _l}g = 6\pi \eta rv

η=2r2ρlgv\eta = {{2{r^2}{\rho _l}g} \over v}

=2×(2×10−3)2×1750×109×3.5×10−3×4= {{2 \times {{(2 \times {{10}^{ - 3}})}^2} \times 1750 \times 10} \over {9 \times 3.5 \times {{10}^{ - 3}} \times 4}}

=11= 11 poise

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