Verified Solution • 2025–26 Session moderate

QJEEM22Ph6885: JEE Main 2022 Physics - Class 11 JEEM22Ph6885 Solution: 7 mol of a certain monoatomic ideal gas undergoes a temperature …

7 mol of a certain monoatomic ideal gas undergoes a temperature increase of 40 K40 \mathrm{~K} at constant pressure. The increase in the internal energy of the gas in this process is :

(Given R=8.3 JK−1 mol−1\mathrm{R}=8.3 \,\mathrm{JK}^{-1} \mathrm{~mol}^{-1} )

Multiple Choice Options

  • A 5810 J
  • B 3486 J
  • C 11620 J
  • D 6972 J

Step-by-Step Verified Solution

ΔU=nCvΔT\Delta U = n{C_v}\Delta T

=7×3R2×40= 7 \times {{3R} \over 2} \times 40

=3486 J= 3486\,J

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