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QJEEM22Ph65c4: JEE Main 2022 Physics - Class 11 JEEM22Ph65c4 Solution: If the initial velocity in horizontal direction of a projectile …

If the initial velocity in horizontal direction of a projectile is unit vector i^\hat{i} and the equation of trajectory is y=5x(1−x)y=5 x(1-x) . The yy component vector of the initial velocity is ______________ j^\hat{j} . ( Take\mathrm{Take} g=10 m/s2)\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)

Step-by-Step Verified Solution

If the initial velocity in the horizontal direction of a projectile is represented by the unit vector i^\hat{i} and the equation of the trajectory is given by y=5x(1−x)y = 5x(1 - x) , we need to find the yy component vector of the initial velocity. (Given: g=10 m/s2g = 10 \mathrm{\ m/s^2} )

The trajectory equation can be expanded as:

y=5x−5x2y = 5x - 5x^2

In the general form of a projectile's trajectory: y=xtan⁡θ−12gx2v02y = x \tan \theta - \frac{1}{2} \frac{g x^2}{v_0^2}

Here, the equation compares as follows:

tan⁡θ=5=uyux\tan \theta = 5 = \frac{u_y}{u_x}

Given that the initial horizontal velocity component, uxu_x , is 1 (unit vector i^\hat{i} ), we can find uyu_y from the relationship:

uy=5×1=5u_y = 5 \times 1 = 5

Therefore, the yy component vector of the initial velocity is 5 j^\hat{j} .

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