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QJEEM22Ph6329: JEE Main 2022 Physics - Class 11 JEEM22Ph6329 Solution: The first overtone frequency of an open organ pipe is equal to…

The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm. The length of the open organ pipe is _____________ cm.

Step-by-Step Verified Solution

2×(V2L0)=(V4Lc)2 \times \left( {{V \over {2{L_0}}}} \right) = \left( {{V \over {4{L_c}}}} \right)

⇒L0=4Lc\Rightarrow {L_0} = 4{L_c}

=4×20= 4 \times 20

=80= 80 cm

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