Verified Solution • 2025–26 Session moderate

QJEEM22Ph5b0e: JEE Main 2022 Physics - Class 12 JEEM22Ph5b0e Solution: Two light beams of intensities in the ratio of 9 : 4 are…

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be :

Multiple Choice Options

  • A 2:03
  • B 0.722916667
  • C 25 : 169
  • D 25:01:00

Step-by-Step Verified Solution

Imax⁡Imin⁡=(I1+I2I1−I2)2=(51)2{{{I_{\max }}} \over {{I_{\min }}}} = {\left( {{{\sqrt {{I_1}} + \sqrt {{I_2}} } \over {\sqrt {{I_1}} - \sqrt {{I_2}} }}} \right)^2} = {\left( {{5 \over 1}} \right)^2}

=251= {{25} \over 1}

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