Verified Solution • 2025–26 Session moderate

QJEEM22Ph5995: JEE Main 2022 Physics - Class 12 JEEM22Ph5995 Solution: A bar magnet having a magnetic moment of 2.0 10 5 JT 1 , is…

A bar magnet having a magnetic moment of 2.0 ×\times 105 JT −- 1, is placed along the direction of uniform magnetic field of magnitude B = 14 ×\times 10 −- 5 T. The work done in rotating the magnet slowly through 60 ∘^\circ from the direction of field is :

Multiple Choice Options

  • A 14 J
  • B 8.4 J
  • C 4 J
  • D 1.4 J

Step-by-Step Verified Solution

U=−M→ . B→U = - \overrightarrow M \,.\,\overrightarrow B

So Uf−Ui=−MB(1−cos⁡θ){U_f} - {U_i} = - MB(1 - \cos \theta )

=−14J= - 14J

So W=−ΔU=14JW = - \Delta U = 14J

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