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QJEEM22Ph5772: JEE Main 2022 Physics - Class 11 JEEM22Ph5772 Solution: The bulk modulus of a liquid is 3 10 10 Nm 2 . The pressure…

The bulk modulus of a liquid is 3 ×\times 1010 Nm −- 2. The pressure required to reduce the volume of liquid by 2% is :

Multiple Choice Options

  • A 3 ×\times 108 Nm −- 2
  • B 9 ×\times 108 Nm −- 2
  • C 6 ×\times 108 Nm −- 2
  • D 12 ×\times 108 Nm −- 2

Step-by-Step Verified Solution

∵\because B=ΔP(−ΔVV)B = {{\Delta P} \over {\left( { - {{\Delta V} \over V}} \right)}}

⇒ΔP=3×1010×(0.02)\Rightarrow \Delta P = 3 \times {10^{10}} \times (0.02)

=6×108= 6 \times {10^8} N/m2

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