QJEEM22Ph562c: JEE Main 2022 Physics - Class 11 JEEM22Ph562c Solution: A person moved from A to B on a circular path as shown in…

Distance travelled = 60 m

$\Rightarrow$ Angle covered = 135 $^\circ$

Displacement $= 2R\sin \left( {{{135^\circ } \over 2}} \right)$

$= 2\left( {{{60} \over {135}} \times {{180} \over \pi }} \right){\left[ {{{1 - \cos (135^\circ )} \over 2}} \right]^{1/2}}$

$= 2\left( {{{80} \over \pi }} \right){(0.85)^{1/2}}$

$\approx 47$ m