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QJEEM22Ph4fd0: JEE Main 2022 Physics - Class 12 JEEM22Ph4fd0 Solution: A vertical electric field of magnitude 4.9 × 10 5 N/C just…

A vertical electric field of magnitude 4.9 × 105 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be :

(Given : g = 9.8 m/s2)

Multiple Choice Options

  • A 1.6 × 10−9 C
  • B 2.0 × 10−9 C
  • C 3.2 × 10−9 C
  • D 0.5 × 10−9 C

Step-by-Step Verified Solution

Since the droplet is at rest

⇒ Net force = 0

⇒ mg = qE

⇒ q=mgE = 2 × 10−9 C

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