QJEEM22Ph4fa6: JEE Main 2022 Physics - Class 11 JEEM22Ph4fa6 Solution: A rolling wheel of 12 kg is on an inclined plane at position P…

For rolling wheel

$[12g\sin \alpha - 3g\sin \alpha ] \times R = (2 \times 12{R^2} + 3{R^2}) \times {a \over R}$

$\Rightarrow {{9g\sin \alpha } \over {27}} = a$

$\Rightarrow a = {{g\sin \alpha } \over 3}$

$\therefore$ $v = \sqrt {2 \times {{g\sin \alpha } \over 3} \times {h \over {\sin \alpha }}} = \sqrt {{2 \over 3}gh}$

$= {1 \over 2} \times \sqrt {{8 \over 3}gh}$

$\therefore$ $x = {8 \over 3} = 2.67$