Verified Solution • 2025–26 Session moderate

QJEEM22Ph4da7: JEE Main 2022 Physics - Class 12 JEEM22Ph4da7 Solution: The maximum and minimum voltage of an amplitude modulated…

The maximum and minimum voltage of an amplitude modulated signal are 60 V60 \mathrm{~V} and 20 V20 \mathrm{~V} respectively. The percentage modulation index will be :

Multiple Choice Options

  • A 0.50%
  • B 50%
  • C 2%
  • D 30%

Step-by-Step Verified Solution

Percentage modulation

μ=Vmax⁡−Vmin⁡Vmax⁡+Vmin⁡×100\mu = {{{V_{\max }} - {V_{\min }}} \over {{V_{\max }} + {V_{\min }}}} \times 100

=60−2060+20×100= {{60 - 20} \over {60 + 20}} \times 100

=50%= 50\%

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