QJEEM22Ph4ad9: JEE Main 2022 Physics - Class 11 JEEM22Ph4ad9 Solution: A particle of mass m is moving in a circular path of constant…

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QJEEM22Ph4ad9: JEE Main 2022 Physics - Class 11 JEEM22Ph4ad9 Solution: A particle of mass m is moving in a circular path of constant…

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration (a) is varying with time t as a = k²rt², where k is a constant. The power delivered to the particle by the force acting on it is given as

Multiple Choice Options

A zero
B mk2r2t2
C mk2r2t
D mk2rt

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Accepted Answer

$a_{r} = k^{2} r t^{2} = \frac{v^{2}}{r}$

$\Rightarrow v^{2} = k^{2} r^{2} t^{2}$ or $v = k r t$

and $\frac{d | v |}{d t} = k r$

$\Rightarrow a_{t} = k r$

$\Rightarrow | \overset{―}{F} . \overset{―}{v} | = (m k r) (k r t)$

$= m k^{2} r^{2} t =$ power delivered

QJEEM22Ph4ad9: JEE Main 2022 Physics - Class 11 JEEM22Ph4ad9 Solution: A particle of mass m is moving in a circular path of constant…

Multiple Choice Options

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