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QJEEM22Ph4863: JEE Main 2022 Physics - Class 11 JEEM22Ph4863 Solution: A force on an object of mass 100 g is ( 10 i ^ + 5 j ^ ) N. The …

A force on an object of mass 100 g is (10i^+5j^) N. The position of that object at t = 2 s is (ai^+bj^) m after starting from rest. The value of ab will be ___________.

Step-by-Step Verified Solution

F→=ma→

⇒a→=100i^+50j^

So, S→=12a→t2

12(100i^+50j^)22

=200i^+100j^ m

so a = 200 m and b = 100 m

so ab=2

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