Verified Solution • 2025–26 Session moderate

QJEEM22Ph447a: JEE Main 2022 Physics - Class 12 JEEM22Ph447a Solution: As shown in the figure, after passing through the medium 1 .…

As shown in the figure, after passing through the medium 1 . The speed of light v2v_{2} in medium 2 will be :

(\left(\right. Given c=3×108 ms−1\mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1} )

JEE Main 2022 (Online) 28th July Morning Shift Physics - Geometrical Optics Question 81 English

Multiple Choice Options

  • A 1.0×108 ms−11.0 \times 10^{8} \mathrm{~ms}^{-1}
  • B 0.5×108 ms−10.5 \times 10^{8} \mathrm{~ms}^{-1}
  • C 1.5×108 ms−11.5 \times 10^{8} \mathrm{~ms}^{-1}
  • D 3.0×108 ms−13.0 \times 10^{8} \mathrm{~ms}^{-1}

Step-by-Step Verified Solution

V=1με=1μrεrμ0ε0V = {1 \over {\sqrt {\mu \varepsilon } }} = {1 \over {\sqrt {{\mu _r}{\varepsilon _r}{\mu _0}{\varepsilon _0}} }}

⇒V2=c9=108\Rightarrow {V_2} = {c \over {\sqrt 9 }} = {10^8} m/s

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