QJEEM22Ph4225: JEE Main 2022 Physics - Class 11 JEEM22Ph4225 Solution: A particle executes simple harmonic motion. Its amplitude is 8…

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QJEEM22Ph4225: JEE Main 2022 Physics - Class 11 JEEM22Ph4225 Solution: A particle executes simple harmonic motion. Its amplitude is 8…

A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ___________ s.

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Accepted Answer

A = 8 cm

T = 6 s

$A \cos (\frac{2 π t}{T}) = \frac{A}{2}$

$\Rightarrow \frac{2 π t}{T} = \frac{π}{3}$

or $t = \frac{T}{6} = 1 s$

QJEEM22Ph4225: JEE Main 2022 Physics - Class 11 JEEM22Ph4225 Solution: A particle executes simple harmonic motion. Its amplitude is 8…

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