QJEEM22Ph41c5: JEE Main 2022 Physics - Class 11 JEEM22Ph41c5 Solution: A torque meter is calibrated to reference standards of mass,…

We know that, torque applied on a rotating body,

$\begin{aligned}\tau &=\text { Force } \times \text { Perpendicular distance } \\\\\Rightarrow \quad[\tau] &=\left[\mathrm{MLT}^{-2}\right][\mathrm{L}] \Rightarrow[\tau]=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]\end{aligned}$

$\Rightarrow {{\Delta \tau } \over \tau } = {{\Delta M} \over M} + 2{{\Delta L} \over L} + 2{{\Delta T} \over T}$

$= 5 \times 5\% = 25\%$