QJEEM22Ph3e08: JEE Main 2022 Physics - Class 11 JEEM22Ph3e08 Solution: The force required to stretch a wire of cross-section 1  …

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QJEEM22Ph3e08: JEE Main 2022 Physics - Class 11 JEEM22Ph3e08 Solution: The force required to stretch a wire of cross-section 1  …

The force required to stretch a wire of cross-section $1 {cm}^{2}$ to double its length will be : (Given Yong's modulus of the wire $= 2 \times 10^{11} N / m^{2}$ )

Multiple Choice Options

A 1×107 N
B 1.5×107 N
C 2×107 N
D 2.5×107 N

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Accepted Answer

$A = 1$ cm²

$Y = \frac{F l}{A Δ l}$

$F = \frac{Y A Δ l}{l} = \frac{2 \times 10^{11} \times 10^{- 4} \times l}{l}$

$= 2 \times 10^{7}$ N

QJEEM22Ph3e08: JEE Main 2022 Physics - Class 11 JEEM22Ph3e08 Solution: The force required to stretch a wire of cross-section 1 &nbsp;…

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QJEEM22Ph3e08: JEE Main 2022 Physics - Class 11 JEEM22Ph3e08 Solution: The force required to stretch a wire of cross-section 1 …